Double Nickels on the Dime

HOW TO SOLVE Creamy's birthday puzzle.

Each of the dominoes can be mathematically assigned to one of the twelve positions of a standard clock face:

 1 o'clock domino ⇨ 4,4  (4 ÷ 4 = 1)
 2 o'clock domino ⇨ 6,4  (6 − 4 = 2)
 3 o'clock domino ⇨ 6,3  (6 − 3 = 3)
 4 o'clock domino ⇨ 6,2  (6 − 2 = 4)
 5 o'clock domino ⇨ 3,2  (3 + 2 = 5)
 6 o'clock domino ⇨ 3,3  (3 + 3 = 6)
 7 o'clock domino ⇨ 5,2  (5 + 2 = 7)
 8 o'clock domino ⇨ 5,3  (5 + 3 = 8)
 9 o'clock domino ⇨ 5,4  (5 + 4 = 9)
10 o'clock domino ⇨ 5,5  (5 + 5 = 10)
11 o'clock domino ⇨ 5,6  (5 + 6 = 11)
12 o'clock domino ⇨ 4,3  (4 × 3 = 12)